A solution of sodium trioxocarbonate (IV) contains 10.6g in 250cm3 of solution. Calculate the concentration of the solution. [Na2CO3 = 106.0]

Answer Details

To calculate the concentration of the sodium trioxocarbonate (IV) solution, we need to use the formula: Concentration (in mol dm^-3) = (mass ÷ molar mass) ÷ volume Firstly, we need to calculate the number of moles of Na₂CO₃ in the solution: mass of Na₂CO₃ = 10.6 g molar mass of Na₂CO₃ = 106.0 g mol^-1 Number of moles of Na₂CO₃ = mass/molar mass = 10.6/106.0 = 0.1 mol Next, we can use the formula above to calculate the concentration: Concentration (in mol dm^-3) = (mass ÷ molar mass) ÷ volume Volume = 250 cm³ = 0.25 dm³ Concentration (in mol dm^-3) = (0.1 mol ÷ 0.25 dm³) = 0.4 mol dm^-3 Therefore, the concentration of the sodium trioxocarbonate (IV) solution is 0.4 mol dm^-3. The correct option is (A) 0.4 mol dm^-3.