A solution of sodium trioxocarbonate (IV) contains 10.6g in 250cm3 of solution. Calculate the concentration of the solution. [Na2CO3 = 106.0]

Assessment: WAEC SSCE - Chemistry - 2010 (Objective) Subject: Chemistry

Question 1 Report

A solution of sodium trioxocarbonate (IV) contains 10.6g in 250cm3 of solution. Calculate the concentration of the solution. [Na2CO3 = 106.0]
Answer Details
To calculate the concentration of the sodium trioxocarbonate (IV) solution, we need to use the formula: Concentration (in mol dm-3) = (mass ÷ molar mass) ÷ volume Firstly, we need to calculate the number of moles of Na2CO3 in the solution: mass of Na2CO3 = 10.6 g molar mass of Na2CO3 = 106.0 g mol-1 Number of moles of Na2CO3 = mass/molar mass = 10.6/106.0 = 0.1 mol Next, we can use the formula above to calculate the concentration: Concentration (in mol dm-3) = (mass ÷ molar mass) ÷ volume Volume = 250 cm3 = 0.25 dm3 Concentration (in mol dm-3) = (0.1 mol ÷ 0.25 dm3) = 0.4 mol dm-3 Therefore, the concentration of the sodium trioxocarbonate (IV) solution is 0.4 mol dm-3. The correct option is (A) 0.4 mol dm-3.

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