Factorize \(6x^2 + 7x - 20\)

Assessment: WAEC SSCE - General Mathematics - 2001 (Objective) Subject: General Mathematics

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Factorize \(6x^2 + 7x - 20\)

Answer Details
To factorize \(6x^2 + 7x - 20\), we need to find two numbers that multiply to -120 (the product of the leading coefficient, 6, and the constant, -20) and add up to the coefficient of the middle term, 7. These numbers are 15 and -8. Therefore, we can write: \begin{align*} 6x^2 + 7x - 20 &= 6x^2 + 15x - 8x - 20 \\ &= 3x(2x+5) - 4(2x+5) \\ &= (3x-4)(2x+5) \end{align*} So the factorization of \(6x^2 + 7x - 20\) is \((3x-4)(2x+5)\).
Read lesson note on Algebraic Expressions (WAEC)
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