If the force of a charge of 0.2 coulomb in an electric field is 4N, then the electric field intensity of the field is

Question 1 Report

If the force of a charge of 0.2 coulomb in an electric field is 4N, then the electric field intensity of the field is

0.8

0.8N/C

20.0N/C

4.2N/C

Answer Details

Field intensity = $\frac{f o r c e}{c h a r g e}$

$\frac{4}{0.2}$ = 20N/C

Read lesson note on Electric Field (WAEC)

Electric Field

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