A milliameter with full scale deflection of 10mA has an internal resistance of 5 ohms. It would be converted to an ammeter with a full scale deflection of 1...

Question 1 Report

A milliameter with full scale deflection of 10mA has an internal resistance of 5 ohms. It would be converted to an ammeter with a full scale deflection of 1A by connecting a resistance of

\frac{5}{99}

ohms in series with it

\frac{5}{99}

ohms in parallel with it

\frac{99}{5}

ohms in series with it

\frac{99}{5}

ohms in parallel with it

2 ohms in series with it

Answer Details

I = 1 - (10 x 10-3)

= 0.99A

IR = 10 x 10 x 10-3 x 5

R = $\frac{5}{99}$ $Ω$

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Capacitors

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