The volume of 0.354g of helium at 273°C and 114cm of mercury pressure is 2667cm$^{3}$. Calculate the volume

Assessment: JAMB UTME - Physics - 2019 Subject: Physics

Question 1 Report

2000.25 cm

^{3}

200.025 cm

^{3}

4003.27 cm

^{3}

2010.25 cm

^{3}

Answer Details

m = 0.354g, T $_{1}$ = 273°C = 273 + 273 = 576K
P $_{1}$ = 114cmHg, V $_{1}$ = 2667cm $^{3}$ at STP
T $^{2}$ = 273K, P $_{2}$ = 76cmHg, V $_{2}$ = ?

P

^{1}

V

^{1}

T

^{1}

=

P

^{2}

V

^{2}

T

^{1}

V

_{2}

=

114 × 2667 × 27376 × 576

=

2000.25cm

^{3}

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