The graph given is for the relation y = 2x2 + x - 1. Find the minimum value of y
Answer Details
To find the minimum value of y for the given relation y = 2x^2 + x - 1, we need to locate the vertex of the parabolic graph.
The vertex of a parabola with equation y = ax^2 + bx + c is given by the coordinates (-b/2a, c - b^2/4a).
In this case, a = 2, b = 1, and c = -1. Substituting these values into the formula, we get:
Vertex x-coordinate = -b/2a = -1/(2*2) = -1/4
Vertex y-coordinate = 2(-1/4)^2 + (1/4) - 1 = -1.25
Therefore, the minimum value of y is -1.25.
So the correct option is (C) -1.25.