If the change in free energy of a system is -899 Jmol-1 and the entropy change is 10Jmol-1k-1 at 250C, calculate the enthalpy change.

Assessment: JAMB UTME - Chemistry - 2014 Subject: Chemistry

Question 1 Report

If the change in free energy of a system is -899 Jmol-1 and the entropy change is 10Jmol-1k-1 at 250C, calculate the enthalpy change.
Answer Details
The enthalpy change can be calculated using the formula: ΔG = ΔH - TΔS where ΔG is the change in free energy, ΔH is the change in enthalpy, ΔS is the change in entropy, and T is the temperature in Kelvin. Plugging in the values given: -899 Jmol-1 = ΔH - (250+273)K * 10Jmol-1K-1 Solving for ΔH: ΔH = -899 Jmol-1 + (523K * 10Jmol-1K-1) ΔH = -899 Jmol-1 + 5230 Jmol-1 ΔH = +4331 Jmol-1 Therefore, the enthalpy change is +4331 Jmol-1, which corresponds to +2081 Jmol-1.

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