Cr2O2−7 2 − 7 (aq) + H2O(1)⇌ 2CrO 2−4 2 − 4 (aq) + 2H + (aq) What happens to the reaction above when the hydrogen ion concentration is increased?

Cr2O$\frac{2-}{7}$ (aq) + H2O(1)⇌ 2CrO $\frac{2-}{4}$ (aq) + 2H + (aq)

What happens to the reaction above when the hydrogen ion concentration is increased?

Answer Details

In the given chemical reaction, Cr2O2−7 ions react with water to form 2CrO 2−4 ions and hydrogen ions (H+). This reaction is in equilibrium, meaning the reactants are forming products and the products are forming reactants at the same rate. According to Le Chatelier's principle, when a stress is applied to a system in equilibrium, the system will shift to counteract the stress. In this case, increasing the hydrogen ion concentration will increase the stress on the equilibrium system. To counteract this stress, the system will shift to consume the additional hydrogen ions. Since hydrogen ions are one of the products of the reaction, the system will shift to form more reactants and less products. Therefore, the equilibrium position will shift to the left. So, the correct answer is (D) the equilibrium position will shift to the left.