A 12V battery has an internal resistance of 0.5W.If a cable of 1.0W resistance is connected across the two terminals of the battery, the current drawn from ...

Answer Details

The problem provides the voltage and internal resistance of a 12V battery and the resistance of an external cable that is connected to the battery terminals. To find the current drawn from the battery, we can use Ohm's law, which states that the current through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. First, we need to calculate the total resistance in the circuit. The total resistance is the sum of the internal resistance of the battery and the resistance of the external cable. Therefore, Total Resistance = Internal Resistance of Battery + Resistance of External Cable = 0.5W + 1.0W = 1.5W Next, we can use Ohm's law to find the current drawn from the battery: Current = Voltage / Total Resistance = 12V / 1.5W = 8.0A Therefore, the current drawn from the battery is 8.0A. So, the correct option is 8.0A.