A body is projected from the earth's surface with the intention of letting it escape from the earth's gravitational field. What is the minimum escape veloci...

Answer Details

The minimum escape velocity of a body is the velocity required to escape from the gravitational field of a planet, which means that the body will move away from the planet and never return. The formula for escape velocity is given by: v = √(2GM/r) where G is the universal gravitational constant, M is the mass of the planet, and r is the distance from the center of the planet to the point where the body is located. In this case, the planet is Earth, with a radius of 6.4 x 10^3 km, and g = 10 m/s^2. The mass of Earth is approximately 5.97 x 10^24 kg. The distance from the center of the planet to the surface is equal to the radius of the planet. Substituting these values into the formula, we get: v = √(2 x 6.67 x 10^-11 x 5.97 x 10^24 / 6.4 x 10^3) v ≈ 11.2 km/s Therefore, the minimum escape velocity of the body is approximately 11 km/s, which is closest to option D, 11 kms^-1.