Two parallel plates at a distance of 8.0 x 10-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field stre...

Assessment: JAMB UTME - Physics - 1995 Subject: Physics

Question 1 Report

Two parallel plates at a distance of 8.0 x 10-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field strength?
Answer Details
The electric field strength between two parallel plates can be calculated using the formula E = V/d, where V is the potential difference between the plates, and d is the distance between the plates. In this case, the potential difference between the plates is given as 600 volts, and the distance between the plates is given as 8.0 x 10^-3 meters. So, substituting these values in the formula, we get: E = V/d = 600 / (8.0 x 10^-3) = 75,000 V/m Therefore, the electric field strength between the parallel plates is 75,000 V/m, which corresponds to option D.

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