An electric current of 2 amperes flows in a heating coil of resistance 50 ohms for 3 minutes 20 seconds. Determine the heat produced

Assessment: JAMB UTME - Physics - 1995 Subject: Physics

Question 1 Report

An electric current of 2 amperes flows in a heating coil of resistance 50 ohms for 3 minutes 20 seconds. Determine the heat produced
Answer Details
Heat energy = Elect. energy

heat energy= I2RT

= 2 X 2 X 50 X 200

= 40000J

to convert to kJ, divide J by 1000

hence,  40000 1000  = 40kJ

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