If 2√3−√2√3+2√2 2 3 − 2 3 + 2 2 = m + n √ 6..

Question 1 Report

If $\frac{2 \sqrt{3} - \sqrt{2}}{\sqrt{3} + 2 \sqrt{2}}$ = m + n √ 6, find the values of m and n respectively.

1, − 2

− 2, n = 1

\frac{- 2}{5}

, 1

\frac{2}{3}

Answer Details

$\frac{2 \sqrt{3} - \sqrt{2}}{\sqrt{3} + 2 \sqrt{2}}$ = m + n√6
$\frac{2 \sqrt{3} - \sqrt{2}}{\sqrt{3} + 2 \sqrt{2}}$ x $\frac{\sqrt{3} - 2 \sqrt{2}}{\sqrt{3} - \sqrt{2}}$

$\frac{2 \sqrt{3} (\sqrt{3} - 2 \sqrt{2}) - \sqrt{2} (\sqrt{3} - 2 \sqrt{2})}{\sqrt{3} (\sqrt{3} - 2 \sqrt{2}) + 2 \sqrt{2} (\sqrt{3} - 2 \sqrt{2})}$
$\frac{2 \times 3 - 4 \sqrt{6} - 6 + 2 \times 2}{3 - 2 \sqrt{6} + 2 \sqrt{6} - 4 \times 2}$
= $\frac{6 - 4 \sqrt{6} - \sqrt{6} + 4}{3 - 8}$
= $\frac{0 - 4 \sqrt{6} - 6}{5}$
= $\frac{10 - 5 \sqrt{6}}{5}$
= − 2 + √6
∴ m + n $\sqrt{6}$ = − 2 + √6
m = − 2, n = 1

Read lesson note on Surds (radicals) (WAEC)

Surds (radicals)

View Answer

If 2√3−√2√3+2√2 2 3 − 2 3 + 2 2 = m + n √ 6, find the values of m and n respectively.

Download The App On Google Playstore