A man covered a distance of 50 miles on his first trip, on a later trip he traveled 300 miles while going 3 times as fast. His new time compared with the ol...

A man covered a distance of 50 miles on his first trip, on a later trip he traveled 300 miles while going 3 times as fast. His new time compared with the old distance was?

Answer Details

Let's denote the man's speed on his first trip as "s". On his first trip, he covered a distance of 50 miles, so his time would be: time = distance / speed = 50 / s On his later trip, he traveled 300 miles while going 3 times as fast, so his new speed would be: new speed = 3s His time for the later trip would then be: time = distance / speed = 300 / (3s) = 100 / s So the ratio of his new time to his old time would be: new time / old time = (100/s) / (50/s) = 100/50 = 2 Therefore, his new time compared to his old time is twice as much. In simpler terms, the man covered a longer distance on his second trip but also traveled faster. Even though he traveled faster on the second trip, the increased distance resulted in his new time being twice as much as his old time.