Question 1 Report
You are provided with a glass block, plane mirror, and optical pins.
(b)i. Explain the term refractive index and give a mathematical expression for it in terms of wavelength.
ii. State the conditions necessary for total internal reflection to occur for a given pair of media.
The block is traced as ABCD, the width is measured as \(W = 5.0\ \text{cm}\). For each angle of incidence the emergent ray is fixed by no-parallax pins \(P_3\) and \(P_4\), and the angles \(\theta\) and \(e\) together with the lateral displacement \(d\) are measured directly from the traces. The full set of readings and the derived quantities \(m = \sin e\) and \(n = \cos\!\left(\dfrac{\theta}{2}\right)\) are tabulated below.
| \(i/^{\circ}\) | \(\theta/^{\circ}\) | \(e/^{\circ}\) | \(d/\text{cm}\) | \(m = \sin e\) | \(n = \cos\left(\frac{\theta}{2}\right)\) |
|---|---|---|---|---|---|
| 10 | 10.4 | 10.0 | 3.00 | 0.174 | 0.996 |
| 20 | 19.0 | 20.4 | 3.90 | 0.349 | 0.986 |
| 30 | 20.0 | 30.0 | 6.00 | 0.500 | 0.985 |
| 40 | 30.0 | 40.0 | 7.00 | 0.643 | 0.966 |
| 50 | 30.0 | 50.0 | 7.50 | 0.766 | 0.966 |
Sample evaluations: for \(i = 30^{\circ}\), \(m = \sin 30.0^{\circ} = 0.500\) and \(n = \cos\!\left(\tfrac{20.0^{\circ}}{2}\right) = \cos 10.0^{\circ} = 0.985\). For \(i = 50^{\circ}\), \(m = \sin 50.0^{\circ} = 0.766\) and \(n = \cos 15.0^{\circ} = 0.966\).
Two points on the line of best fit are \((n_1, m_1) = (0.996,\ 0.174)\) and \((n_2, m_2) = (0.966,\ 0.766)\).
\[ s = \frac{m_2 - m_1}{n_2 - n_1} = \frac{0.766 - 0.174}{0.966 - 0.996} = \frac{0.592}{-0.030} = -19.7 \]The slope is \(s = -19.7\) (magnitude \(19.7\)).
With \(W = 5.0\ \text{cm}\) and \(s = -19.7\):
\[ q = 2Ws = 2 \times 5.0\ \text{cm} \times (-19.7) = -197\ \text{cm} \]Hence \(|q| = 197\ \text{cm}\).
The refractive index is the ratio of the velocity of light in air (vacuum) to the velocity of light in a material medium as light waves pass from air into the medium. In terms of wavelength, since the frequency is unchanged on refraction,
\[ n = \frac{\lambda_{1}}{\lambda_{2}} \]where \(\lambda_{1}\) is the wavelength in air, \(\lambda_{2}\) is the wavelength in the material, and \(n\) is the refractive index of the material.
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