An electron of mass 9.1 x 10-31 kg moves with a speed of 107ms-1. Calculate the wavelength of the associates wave[h = 6.6 x 10-34Js]
Question 1 Report
An electron of mass 9.1 x 10-31 kg moves with a speed of 107ms-1. Calculate the wavelength of the associates wave[h = 6.6 x 10-34Js]
Answer Details
The wavelength of the associated wave of a moving particle can be determined using the de Broglie equation, which relates the particle's momentum to its wavelength:
λ = h / p
where λ is the wavelength, h is Planck's constant, and p is the momentum of the particle.
We can determine the momentum of the electron using the formula:
p = m * v
where p is the momentum, m is the mass, and v is the velocity.
Substituting the given values, we get:
p = (9.1 x 10^-31 kg) * (10^7 ms^-1) = 9.1 x 10^-24 kgms^-1
Substituting p into the de Broglie equation, we get:
λ = h / p = (6.6 x 10^-34 Js) / (9.1 x 10^-24 kgms^-1) = 7.25 x 10^-11 m
Therefore, the wavelength of the associated wave is 7.25 x 10^-11 m.
The correct option is (c) 7.25 x 10^-11 m.
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