In a hydraulic press, a force of 40N is applied to the smaller priston of area 10cm2. If the area of the larger piston is 200cm2, calculate the force obtain...

In a hydraulic press, a force of 40N is applied to the smaller priston of area 10cm². If the area of the larger piston is 200cm², calculate the force obtained

Answer Details

In a hydraulic press, the pressure exerted is constant throughout the system. The pressure exerted is given by the formula: Pressure = Force / Area The force is directly proportional to the product of the pressure and area. F ∝ P.A If F₁ is the force applied on the smaller piston of area A₁, and F₂ is the force on the larger piston of area A₂, then: F₁ / A₁ = F₂ / A₂ Rearranging the formula above to solve for F₂: F₂ = F₁ x (A₂ / A₁) Substituting the values given in the question, we get: F₂ = 40N x (200cm² / 10cm²) = 800N Therefore, the force obtained is 800N. The answer is (a) 800N.