(a)(i) Explain the term co-ordinance. (ii) Calculate the number of individuals with co-dominant blood group. (iii) What is the total number of individuals i...
(ii) Calculate the number of individuals with co-dominant blood group.
(iii) What is the total number of individuals in the table that are able to donate blood to an accident victim with blood group B?
(b) A man whose blood group is heterozygous A is married to a woman whose blood group is AB. With the aid of a genetic diagram, suggest the possible blood groups of their children.
A survey to determine blood groups was carried out on 250 people living in a community. The results are represented in the table below.
Blood group
Percentage
A
8.0
B
14.0
AB
32.8
O
45.2
(a)(i) Co-dominance
Co-dominance is a condition in which both alleles of a gene are fully and equally expressed in a heterozygous individual. Neither allele masks the other. For example, \(I^A\) and \(I^B\) are co-dominant alleles; hence \(I^AI^B\) produces blood group AB.
Survey calculations
Blood group
Percentage
Number out of 250
A
8.0%
20
B
14.0%
35
AB
32.8%
82
O
45.2%
113
(a)(ii) The co-dominant blood group is AB.
\[\frac{32.8}{100}\times250=82\]
Therefore, 82 individuals have the co-dominant blood group.
(a)(iii) A person with blood group B can receive blood from persons with blood groups B and O.
\[\text{Number with group B}=\frac{14.0}{100}\times250=35\]
\[\text{Number with group O}=\frac{45.2}{100}\times250=113\]
\[35+113=148\]
Therefore, 148 individuals can donate blood to the accident victim with blood group B.
(b) Genetic diagram
Heterozygous blood group A man: \(I^Ai\) Blood group AB woman: \(I^AI^B\)
Gametes from the man are \(I^A\) and \(i\), while gametes from the woman are \(I^A\) and \(I^B\).
Punnett square for a heterozygous group A man, \(I^Ai\), and a group AB woman, \(I^AI^B\).
The possible genotypes and phenotypes of the children are:
\(I^AI^A\): blood group A
\(I^Ai\): blood group A
\(I^AI^B\): blood group AB
\(I^Bi\): blood group B
Thus, the possible blood groups are A, AB and B, in the ratio:
\[2\text{ A}:1\text{ AB}:1\text{ B}\]
That is, 50% blood group A, 25% blood group AB and 25% blood group B. No child will have blood group O.
Co-dominance is a condition in which both alleles of a gene are fully and equally expressed in a heterozygous individual. Neither allele masks the other. For example, \(I^A\) and \(I^B\) are co-dominant alleles; hence \(I^AI^B\) produces blood group AB.
Survey calculations
Blood group
Percentage
Number out of 250
A
8.0%
20
B
14.0%
35
AB
32.8%
82
O
45.2%
113
(a)(ii) The co-dominant blood group is AB.
\[\frac{32.8}{100}\times250=82\]
Therefore, 82 individuals have the co-dominant blood group.
(a)(iii) A person with blood group B can receive blood from persons with blood groups B and O.
\[\text{Number with group B}=\frac{14.0}{100}\times250=35\]
\[\text{Number with group O}=\frac{45.2}{100}\times250=113\]
\[35+113=148\]
Therefore, 148 individuals can donate blood to the accident victim with blood group B.
(b) Genetic diagram
Heterozygous blood group A man: \(I^Ai\) Blood group AB woman: \(I^AI^B\)
Gametes from the man are \(I^A\) and \(i\), while gametes from the woman are \(I^A\) and \(I^B\).
Punnett square for a heterozygous group A man, \(I^Ai\), and a group AB woman, \(I^AI^B\).
The possible genotypes and phenotypes of the children are:
\(I^AI^A\): blood group A
\(I^Ai\): blood group A
\(I^AI^B\): blood group AB
\(I^Bi\): blood group B
Thus, the possible blood groups are A, AB and B, in the ratio:
\[2\text{ A}:1\text{ AB}:1\text{ B}\]
That is, 50% blood group A, 25% blood group AB and 25% blood group B. No child will have blood group O.