50cm 3 of a saturated solution of potassium trioxonitrate (V)at 40°C contains 5.05g of the salt. What is the solubility of potassium trioxonitrate (V) at 40...

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The solubility of a substance is the maximum amount of solute that can be dissolved in a given amount of solvent at a specific temperature. In this question, we are given the volume and concentration of a saturated solution of potassium trioxonitrate (V) at 40°C. We can use this information to calculate the solubility of the salt at 40°C. First, we need to convert the given volume from cm³ to dm³ (litres) since the concentration is given in mol dm^-3. 50 cm³ = 50 ÷ 1000 dm³ = 0.05 dm³ The number of moles of potassium trioxonitrate (V) in the solution can be calculated using the formula: moles = concentration × volume The concentration is given as saturated, which means that the solution contains the maximum amount of potassium trioxonitrate (V) that can dissolve at 40°C. Therefore, the concentration is equal to the solubility of the salt at that temperature. So, we have: moles of KNO₃ = solubility × volume = solubility × 0.05 dm³ We are also given the mass of KNO₃ in the solution, which is 5.05 g. We can use the molar mass of KNO₃ (101 g/mol) to calculate the number of moles: moles of KNO₃ = mass ÷ molar mass = 5.05 ÷ 101 = 0.05 mol Now, we can equate the two expressions for the number of moles of KNO₃: solubility × 0.05 = 0.05 solubility = 0.05 ÷ 0.05 = 1 mol dm^-3 Therefore, the solubility of potassium trioxonitrate (V) at 40°C is 1.0 mol dm^-3. Answer: 1.0 mol dm^-3.