The diagram is the graph of \(y = 6 + x - x^2\). The graph intercepts the x- axis at P and R and the y- axis at Q. When \(y = 3\frac{1}{3}\), what is the po...
Question 1 Report
The diagram is the graph of \(y = 6 + x - x^2\). The graph intercepts the x- axis at P and R and the y- axis at Q.
When \(y = 3\frac{1}{3}\), what is the positive value of x?
Answer Details
The given function is \(y = 6 + x - x^2\). We are required to find the value of x when y is equal to \(3\frac{1}{3}\), which is also equal to \(\frac{10}{3}\).
Substituting \(y = \frac{10}{3}\) in the given equation, we get
\[\frac{10}{3} = 6 + x - x^2\]
Rearranging the terms, we get
\[x^2 - x + \frac{8}{3} = 0\]
Solving the quadratic equation, we get two solutions for x, which are \(\frac{4}{3}\) and \(1\frac{1}{2}\). However, we are asked to find the positive value of x, which is \(\boxed{2\frac{1}{5}}\).
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