Calculate the mass of chlorine gas which occupies a volume of 1.12 dm\(^3\) a volume of 1.12 dm\(^3\) at s.t.p [Cl = 35.5, 1 mole og gas occupies 22.4 dm\(^...

Answer Details

The given information includes the volume of chlorine gas and the conditions of temperature and pressure (s.t.p). The formula for calculating the mass of a gas at s.t.p is: mass = (volume of gas at s.t.p in dm³) x (molar mass of gas) / (molar volume at s.t.p) The molar mass of chlorine gas (Cl₂) is 2 x atomic mass of Cl = 2 x 35.5 = 71 g/mol. The molar volume of any gas at s.t.p is 22.4 dm³. Plugging in the values, we get: mass = (1.12 dm³) x (71 g/mol) / (22.4 dm³/mol) = 3.55 g Therefore, the mass of chlorine gas which occupies a volume of 1.12 dm³ at s.t.p is 3.55 g. The correct option is (b) 3.55g.