Consider the following equation: Cr2O2-7(aq) + 14H+(aq) + 6e- → 2Cr3+(ag) + 7H2O(1). The oxidation number of chromium changes from

Consider the following equation: Cr₂O^2-_7(aq) + 14H⁺_(aq) + 6e^- → 2Cr³⁺_(ag) + 7H₂O₍₁₎. The oxidation number of chromium changes from

Answer Details

The oxidation number is a number that represents the charge of an atom in a compound. In the given equation, the chromium atom changes from a +6 oxidation state on the reactant side (Cr₂O^2-_(aq)) to a +3 oxidation state on the product side (2Cr³⁺_(aq)). This means that the oxidation number of chromium has decreased by 3, indicating that it has undergone reduction. Therefore, the correct answer is +6 to +3.