Consider the following equation: Cr2O2-7(aq) + 14H+(aq) + 6e- → 2Cr3+(ag) + 7H2O(1). The oxidation number of chromium changes from

Assessment: WAEC SSCE - Chemistry - 2002 (Objective) Subject: Chemistry

Question 1 Report

Consider the following equation: Cr2O2-7(aq) + 14H+(aq) + 6e- → 2Cr3+(ag) + 7H2O(1). The oxidation number of chromium changes from
Answer Details
The oxidation number is a number that represents the charge of an atom in a compound. In the given equation, the chromium atom changes from a +6 oxidation state on the reactant side (Cr2O2-(aq)) to a +3 oxidation state on the product side (2Cr3+(aq)). This means that the oxidation number of chromium has decreased by 3, indicating that it has undergone reduction. Therefore, the correct answer is +6 to +3.

Download The App On Google Playstore

Everything you need to excel in your exams

Green Bridge CBT Mobile App
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning