Calculate the mass of sodium hydroxide in 5.00 dm3 of a 0.125 mol dm-3 solution. [NaOH = 40 g mol-1]

Assessment: WAEC SSCE - Chemistry - 2002 (Objective) Subject: Chemistry

Question 1 Report

Calculate the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution. [NaOH = 40 g mol^-1]

0.0156 g

0.625 g

1.00 g

25.0 g

Answer Details

To calculate the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution, we need to use the formula: mass = moles × molar mass First, let's calculate the number of moles of NaOH in 5.00 dm³ of the solution: moles = concentration × volume moles = 0.125 mol dm^-3 × 5.00 dm³ moles = 0.625 mol Now, we can use the formula to calculate the mass of NaOH: mass = 0.625 mol × 40 g mol^-1 mass = 25.0 g Therefore, the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution is 25.0 g. Answer: 25.0 g

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Stoichiometry And Chemical Reactions

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Calculate the mass of sodium hydroxide in 5.00 dm3 of a 0.125 mol dm-3 solution. [NaOH = 40 g mol-1]

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