Calculate the mass of sodium hydroxide in 5.00 dm3 of a 0.125 mol dm-3 solution. [NaOH = 40 g mol-1]

Calculate the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution. [NaOH = 40 g mol^-1]

Answer Details

To calculate the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution, we need to use the formula: mass = moles × molar mass First, let's calculate the number of moles of NaOH in 5.00 dm³ of the solution: moles = concentration × volume moles = 0.125 mol dm^-3 × 5.00 dm³ moles = 0.625 mol Now, we can use the formula to calculate the mass of NaOH: mass = 0.625 mol × 40 g mol^-1 mass = 25.0 g Therefore, the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution is 25.0 g. Answer: 25.0 g