Two liquids X and Y having the same mass are supplied with the same quantity of heat. If the temperature rise in X is twice that of Y, the ratio of specific...

Two liquids X and Y having the same mass are supplied with the same quantity of heat. If the temperature rise in X is twice that of Y, the ratio of specific heat capacity of X to that of Y is

Answer Details

The question is asking about the ratio of specific heat capacities of two liquids, X and Y, which have the same mass and are supplied with the same amount of heat. If the temperature rise in X is twice that of Y, then we can use the formula: Q = mcΔT where Q is the amount of heat supplied, m is the mass of the liquid, c is the specific heat capacity, and ΔT is the change in temperature. Since both liquids have the same mass and are supplied with the same amount of heat, we can write: mcΔTx = mcΔTy where ΔTx is the temperature rise in X and ΔTy is the temperature rise in Y. We are given that ΔTx = 2ΔTy, so we can substitute this into the equation to get: mc(2ΔTy) = mcΔTy Simplifying this equation gives: 2cX = cY where cX is the specific heat capacity of liquid X and cY is the specific heat capacity of liquid Y. Therefore, the ratio of specific heat capacity of X to that of Y is 2:1, which means the correct option is: 2:1