What effort will a machine of efficiency 90% apply to lift a load of 180N if its efforts arm is twice as long as its load arm?

What effort will a machine of efficiency 90% apply to lift a load of 180N if its efforts arm is twice as long as its load arm?

Answer Details

M.A. = $\frac{Eff\times V.R.}{100}$

M.A. = $\frac{90\times 2}{100}$

M.A. = 1.8

E = $\frac{L}{M.A.}$

E = $\frac{180}{1.8}$

E = 100N