What effort will a machine of efficiency 90% apply to lift a load of 180N if its efforts arm is twice as long as its load arm?

Question 1 Report

What effort will a machine of efficiency 90% apply to lift a load of 180N if its efforts arm is twice as long as its load arm?

80N

90N

100N

120N

Answer Details

M.A. = $\frac{E f f \times V . R .}{100}$
M.A. = $\frac{90 \times 2}{100}$
M.A. = 1.8
E = $\frac{L}{M . A .}$
E = $\frac{180}{1.8}$
E = 100N

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Simple Machines

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