Question 1 Report

A simple pendulum of length 0.4m has a period of 2s. What is the period a similar pendulum of length 0.8m at the same place?

Answer Details

T2 = √L2×T21L1 $\sqrt{\frac{{L}^{2}\times {T}_{1}^{2}}{{L}_{1}}}$

= √0.8×220.4 $\sqrt{\frac{0.8\times {2}^{2}}{0.4}}$

= 2√2s