A simple pendulum of length 0.4m has a peri..

Question 1 Report

A simple pendulum of length 0.4m has a period of 2s. What is the period a similar pendulum of length 0.8m at the same place?

\sqrt{2} s

√2s

Answer Details

T2 = $\sqrt{\frac{L^{2} \times T_{1}^{2}}{L_{1}}}$

= $\sqrt{\frac{0.8 \times 2^{2}}{0.4}}$

= 2 $\sqrt{2} s$