A train with an initial velocity of 20ms-1 is subjected to a uniform deceleration of 2m-2. The time required to bring the train to a complete halt is?
Answer Details
The problem can be solved using the equation: v^2 = u^2 + 2as Where: v = final velocity (0 m/s) u = initial velocity (20 m/s) a = acceleration (-2 m/s^2) s = distance traveled (unknown) Rearranging the equation to solve for s: s = (v^2 - u^2) / 2a Substituting the given values: s = (0^2 - 20^2) / 2(-2) s = 200 m Now, we can use the equation: v = u + at Where: v = final velocity (0 m/s) u = initial velocity (20 m/s) a = acceleration (-2 m/s^2) t = time (unknown) Solving for t: 0 = 20 - 2t t = 10 s Therefore, the time required to bring the train to a complete halt is 10 seconds. The correct option is 10s.