Solve for x in the equation $5^{x} \times 5^{x + 1} = 25$.

Assessment: WAEC SSCE - Further Mathematics - 2016 (Objective) Subject: Further Mathematics

Question 1 Report

$-2$

$\frac{-1}{2}$

$\frac{1}{2}$

$2$

Answer Details

To solve the equation $5^{x} \times 5^{x + 1} = 25$, we can use the rules of exponents. Since the bases are the same (both are 5), we can add the exponents to get: $$5^{x} \times 5^{x + 1} = 5^{2}$$ $$5^{2x + 1} = 5^{2}$$ Now we can solve for x by equating the exponents: $$2x + 1 = 2$$ $$2x = 1$$ $$x = \frac{1}{2}$$ Therefore, the solution is $\frac{1}{2}$.

Read lesson note on Indices And Logarithmic Functions (WAEC)

Indices And Logarithmic Functions

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