Calculate the mass of sodium hydroxide in 5.00 dm3 of a 0.125 mol dm-3 solution [NaOH = 40 g mol]

Answer Details

To calculate the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution, we need to use the formula: mass = molarity x volume x molecular weight where: - molarity = 0.125 mol dm^-3 (given) - volume = 5.00 dm³ (given) - molecular weight of NaOH = 40 g mol^-1 (given) Substituting the values into the formula, we get: mass = 0.125 mol dm^-3 x 5.00 dm³ x 40 g mol^-1 mass = 25.0 g Therefore, the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution is 25.0 g. The correct option is (d).