Calculate the mass of sodium hydroxide in 5.00 dm3 of a 0.125 mol dm-3 solution [NaOH = 40 g mol]

Assessment: WAEC SSCE - Chemistry - 2001 (Objective) Subject: Chemistry

Question 1 Report

Calculate the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution [NaOH = 40 g mol]

0.0156 g

0.625 g

1.00 g

25. 0 g

Answer Details

To calculate the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution, we need to use the formula: mass = molarity x volume x molecular weight where: - molarity = 0.125 mol dm^-3 (given) - volume = 5.00 dm³ (given) - molecular weight of NaOH = 40 g mol^-1 (given) Substituting the values into the formula, we get: mass = 0.125 mol dm^-3 x 5.00 dm³ x 40 g mol^-1 mass = 25.0 g Therefore, the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm^-3 solution is 25.0 g. The correct option is (d).

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Stoichiometry And Chemical Reactions

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Calculate the mass of sodium hydroxide in 5.00 dm3 of a 0.125 mol dm-3 solution [NaOH = 40 g mol]

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