If y = x sinx, find dy/dx when x = ?/2.

Assessment: JAMB UTME - Mathematics - 2001 Subject: General Mathematics

Question 1 Report

If y = x sinx, find dy/dx when x = ?/2.
Answer Details
To find dy/dx, we need to take the derivative of y with respect to x. Using the product rule of differentiation, we have: dy/dx = (sinx) + (x)(cosx) So, when x = ?/2, we can substitute this value into the expression to get: dy/dx = (sin(?/2)) + (?/2)(cos(?/2)) We know that sin(?/2) = 1 and cos(?/2) = 0, so we can simplify the expression: dy/dx = (1) + (?/2)(0) dy/dx = 1 Therefore, the answer is 1.
Read lesson note on Differentiation (JAMB)
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