Question 1 Report
Cold drinks at the club pool come in two similar cone shaped cups, 9 cm and 12 cm tall.
Between similar solids, lengths scale by \(k\), surface areas by \(k^2\) and volumes by \(k^3\).
(a) The scale factor from the smaller cup to the larger is \(\frac{12}{9} = \frac{4}{3}\). [1]
(b)
(c)
Part (c) runs in the opposite direction to parts (a) and (b), so the scale factor must be inverted before cubing; using \(\left(\frac{4}{3}\right)^3\) would enlarge rather than reduce and give 1517 ml, more than the larger cup itself.
Working with the fractions rather than decimals keeps the arithmetic exact, since \(\frac{16}{9}\) and \(\frac{27}{64}\) both cancel neatly against the given figures.
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