The resale value of a festival wristband depreciates by the same percentage, \(r\%\), each day once the festival sells out. A wristband bought for \(\pounds...

Assessment: Mathematics Specification A 4MA1 | Paper 4 Mock 01 | Structured / Short Answer Subject: Mathematics Specification A - 4MA1

Question 1 Report

The resale value of a festival wristband depreciates by the same percentage, \(r\%\), each day once the festival sells out. A wristband bought for \(\pounds120\) on Day 0 is worth \(\pounds108.30\) on Day 2, as shown in the diagram.

04080120Day 0Day 2£120£108.30Value (£)© EAGLE BEACON GLOBAL
  1. Set up an equation in \(r\) for the value on Day 2. (2)
  2. Solve your equation to find the value of \(r\). (3)

Answer Details

(a) Depreciating by the same percentage \(r\%\) each day means multiplying by \(\left(1-\dfrac{r}{100}\right)\) once per day. After 2 days, this multiplier is applied twice, so the value on Day 2 is \(120\left(1-\dfrac{r}{100}\right)^{2}=108.30\), matching the bar shown on the diagram. [2 marks]

(b) Dividing both sides by \(120\): \(\left(1-\dfrac{r}{100}\right)^{2}=\dfrac{108.30}{120}=0.9025\). Taking the square root of both sides: \(1-\dfrac{r}{100}=\sqrt{0.9025}=0.95\) (taking the positive root, since a resale value multiplier must be positive). Rearranging, \(\dfrac{r}{100}=1-0.95=0.05\), so \(r=5\). [3 marks]

Squaring the daily multiplier to model 2 days' depreciation, rather than doubling the percentage \(r\), reflects that the second day's fall is calculated on the already-reduced Day 1 value, not on the original \(\pounds120\).

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