Question 1 Report
A traffic cone at the entrance to a car park has a base radius of 6 cm and a height of 14 cm. Work out the volume of the cone, giving your answer as a multiple of \(\pi\). (2)
The traffic cone's volume follows the standard formula for a cone, \(V=\dfrac13\pi r^{2}h\), using the given base radius and height.
Substituting the radius \(6\) cm and height \(14\) cm into the cone volume formula: \(V=\dfrac13\pi(6)^{2}(14)\). [1 mark]
Evaluating: \(\dfrac13\pi(36)(14)=\dfrac13\pi(504)=168\pi\) cm\(^{3}\). [1 mark]
Leaving the answer as a multiple of \(\pi\), as requested, avoids any rounding and keeps the value exact; the \(\dfrac13\) divides evenly into \(504\) here, since \(504=3\times168\).
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