Question 1 Report
A school canteen sells trays of home-baked cupcakes at morning break every day this half term to raise funds for sports day. The number of trays, \(x\), must satisfy \(x^{2} - 5x - 14 \lt 0\).
Factorising the quadratic finds the two values where it equals zero; between these two roots a positive quadratic is negative, so the inequality's solution is the interval between them, and a physical restriction (a positive whole number of trays) then lists the valid values.
(a) Two numbers multiplying to \(-14\) and adding to \(-5\) are \(-7\) and \(2\), so \(x^{2}-5x-14 = (x-7)(x+2)\). [2 marks]
(b) Since the graph of \(y=(x-7)(x+2)\) is an upward parabola crossing the \(x\)-axis at \(x=-2\) and \(x=7\), it is negative (below the axis) between these roots: \((x-7)(x+2)\lt0\) when \(-2\lt x\lt7\). [2 marks]
(c) Since \(x\) is a positive whole number of trays, the possible values are \(x=1,2,3,4,5,6\), shown on the number line above with open circles at \(-2\) and \(7\) (both excluded) and the region between shaded. [2 marks]
Everything you need to excel in your exams