A school canteen sells trays of home-baked cupcakes at morning break every day this half term to raise funds for sports day. The number of trays, \(x\), mus...

Assessment: Mathematics Specification A 4MA1 | Paper 4 Mock 01 | Structured / Short Answer Subject: Mathematics Specification A - 4MA1

Question 1 Report

A school canteen sells trays of home-baked cupcakes at morning break every day this half term to raise funds for sports day. The number of trays, \(x\), must satisfy \(x^{2} - 5x - 14 \lt 0\).

  1. Factorise \(x^{2} - 5x - 14\). (2)
  2. Hence solve \(x^{2} - 5x - 14 \lt 0\). (2)
  3. Given that \(x\) is a positive whole number of trays, list the possible values of \(x\), shown on the number line below. (2)
-4-3-2-1012345678© EAGLE BEACON GLOBAL

Answer Details
-4-3-2-1012345678© EAGLE BEACON GLOBAL

Factorising the quadratic finds the two values where it equals zero; between these two roots a positive quadratic is negative, so the inequality's solution is the interval between them, and a physical restriction (a positive whole number of trays) then lists the valid values.

(a) Two numbers multiplying to \(-14\) and adding to \(-5\) are \(-7\) and \(2\), so \(x^{2}-5x-14 = (x-7)(x+2)\). [2 marks]

(b) Since the graph of \(y=(x-7)(x+2)\) is an upward parabola crossing the \(x\)-axis at \(x=-2\) and \(x=7\), it is negative (below the axis) between these roots: \((x-7)(x+2)\lt0\) when \(-2\lt x\lt7\). [2 marks]

(c) Since \(x\) is a positive whole number of trays, the possible values are \(x=1,2,3,4,5,6\), shown on the number line above with open circles at \(-2\) and \(7\) (both excluded) and the region between shaded. [2 marks]

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