A tram inspector is fixing a new sign at point \(C\) along a route. Stop \(A\) and junction \(B\) are \(40\) m apart, angle \(ABC = 35^\circ\), and \(AC = 2...

Assessment: Mathematics Specification A 4MA1 | Paper 3 Mock 01 | Structured / Short Answer Subject: Mathematics Specification A - 4MA1

Question 1 Report

A tram inspector is fixing a new sign at point \(C\) along a route. Stop \(A\) and junction \(B\) are \(40\) m apart, angle \(ABC = 35^\circ\), and \(AC = 25\) m. Two possible positions for \(C\), labelled \(C_1\) and \(C_2\), are shown below.

ABC₁C₂40 m© EAGLE BEACON GLOBAL
  1. Use the sine rule to find the two possible values of angle \(AC_1B\) and angle \(AC_2B\), each correct to 1 decimal place. (3)
  2. Hence work out the two corresponding possible values of angle \(BAC\). (2)
  3. Explain why this information gives two different possible positions for \(C\) rather than one. (1)

Answer Details

This is the ambiguous ("SSA") case of the sine rule: knowing two sides and a non-included angle can give two different triangles, because both an acute angle and its supplement have the same sine.

  1. The sine rule gives \(\frac{\sin(\angle ACB)}{AB}=\frac{\sin B}{AC}\), so \(\sin(\angle ACB)=\frac{40\sin35^\circ}{25}=0.918\). [1 mark] Taking the inverse sine directly gives the acute solution, angle \(AC_1B=\sin^{-1}(0.918)=66.6^\circ\) (1 d.p.). [1 mark] Since \(\sin\theta=\sin(180^\circ-\theta)\), the obtuse solution is angle \(AC_2B=180^\circ-66.6^\circ=113.4^\circ\). [1 mark]
  2. Using the angle sum of a triangle for each case: angle \(BAC_1=180^\circ-35^\circ-66.6^\circ=78.4^\circ\). [1 mark] Angle \(BAC_2=180^\circ-35^\circ-113.4^\circ=31.6^\circ\). [1 mark]
  3. Side \(AC=25\) m is longer than the perpendicular distance from \(A\) to the line through \(B\) but shorter than \(AB=40\) m, so a circular arc of radius \(AC\) centred at \(A\) crosses that line at two distinct points; each crossing gives a valid triangle, which is why two different positions for \(C\) satisfy the given information. [1 mark]

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