Question 1 Report
A shopkeeper buys a box of 90 chocolate bars from a wholesaler to sell in her corner shop. She sells \(\frac{2}{3}\) of the bars individually to customers, and donates \(\frac{1}{9}\) of the bars to a school fair nearby.
This question tests taking two separate fractions of the same total and finding what remains.
(a) Bars sold individually are \(\frac{2}{3}\) of the total:
\[\frac{2}{3} \times 90 = 60 \text{ bars}.\][2]
(b) Bars donated are \(\frac{1}{9}\) of the total:
\[\frac{1}{9} \times 90 = 10 \text{ bars}.\]The bars remaining after both are subtracted from the total:
\[90 - 60 - 10 = 20 \text{ bars}.\][2]
Both fractions here are taken from the same original 90 bars, so the remaining amount is found by direct subtraction rather than by working through a reduced remainder at each stage.
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