The number of oxygen molecules present in 16.0g of the gas is ______? [Avogadro's number = 6.02 x 1023]

Assessment: WAEC SSCE - Chemistry - 2015 (Objective) Subject: Chemistry

Question 1 Report

The number of oxygen molecules present in 16.0g of the gas is ______?
[Avogadro's number = 6.02 x 1023]
Answer Details
The molar mass of oxygen gas (O2) is 32 g/mol. Therefore, 16.0 g of oxygen gas will contain one-half the number of moles as its mass in grams. Number of moles = mass ÷ molar mass Number of moles of O2 in 16.0 g = 16.0 g ÷ 32 g/mol = 0.5 mol Since one mole of any substance contains Avogadro's number of particles (atoms or molecules), the number of oxygen molecules in 0.5 mol of O2 is: Number of molecules = Avogadro's number x Number of moles Number of molecules = 6.02 x 1023 x 0.5 = 3.01 x 1023 Therefore, the correct option is: 3.01 x 1023.
Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)
Read lesson note on Stoichiometry And Chemical Reactions (WAEC)
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