In the reaction H2(g)O → → H2(g) + 1/2O2(g) ΔH = -2436000 KJ, which of the following has no effect on the equilibrium position?

Question 1 Report

In the reaction H2(g)O $\to$ H2(g) + 1/2O2(g)

ΔH = -2436000 KJ, which of the following has no effect on the equilibrium position?

Adding argon to the system

Lowering the temperature

Adding hydrogen to the system

Decreasing the pressure

Increasing the temperature

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