Question 1 Report
(a) (i) What is the difference between the genotype and phenotype of an individual?
(ii) State two factors each which determine each of the terms in (a)(i).
(b) In a breeding experiment, a homozygous dog (BB) was crossed with a homozygous white dog (bb) to produce black puppies in the first filial generation (F1) The second filial generation produced a total of two hundred and forty (240) black and white puppies. With the aid of a genetic diagram, determine:
(i) the number of white puppies
(ii) the number of black puppies in the second filial generation.
The genotype is the genetic constitution of an individual, that is, the actual set of alleles (genes) it carries for a trait, for example BB, Bb or bb. The phenotype is the observable physical or physiological expression of that trait, for example black coat colour or white coat colour, which results from the genotype interacting with the environment.
Genotype is determined by:
Phenotype is determined by:
Let B = allele for black coat (dominant) and b = allele for white coat (recessive).
Parental cross (P): a homozygous black dog (BB) crossed with a homozygous white dog (bb). Each parent contributes one gamete type, so every offspring receives one B and one b allele. All the first filial generation (F1) are therefore Bb (black).
F1 × F1 cross: Bb × Bb. The genetic diagram (Punnett square) below shows the F2 offspring.
From the genetic diagram the F2 genotypes are 1 BB : 2 Bb : 1 bb, giving a phenotypic ratio of 3 black : 1 white.
Total number of F2 puppies = 240.
White puppies (bb) form \(\tfrac{1}{4}\) of the offspring:
\[ \text{White} = \frac{1}{4} \times 240 = 60 \text{ white puppies} \]Black puppies (BB and Bb) form \(\tfrac{3}{4}\) of the offspring:
\[ \text{Black} = \frac{3}{4} \times 240 = 180 \text{ black puppies} \]Answers: 60 white puppies and 180 black puppies in the second filial generation.
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