9.60 g of a gas X occupies the same volume at 0.30 g of hydrogen under the same conditions. Calculate the molar mass of X [H = 1]

The molar volume of gases at standard temperature and pressure (STP) is the same for all gases. This means that equal volumes of gases at STP contain equal numbers of molecules. The molar volume of a gas at STP is 22.4 L/mol. From the question, we know that: mass of gas X = 9.60 g mass of hydrogen = 0.30 g We can use the molar masses of hydrogen and gas X to calculate the number of moles of each gas: moles of hydrogen = mass/molar mass = 0.30 g/1 g/mol = 0.30 mol moles of gas X = mass/molar mass = 9.60 g/molar mass Since the two gases occupy the same volume, we can equate their molar volumes: moles of hydrogen/volume = moles of gas X/volume Substituting the values we know: 0.30/22.4 = (9.60/molar mass)/22.4 Solving for the molar mass of gas X: molar mass = (9.60/0.30) x 1 = 32 g/mol Therefore, the molar mass of gas X is 32 g/mol. Answer: 32g mol ^-1