Calculate the heat energy required to change 0.1kg of ice at 0oC to water boiling at 100oC. (Specific heat capacity of water = 4200 J kg-1K-1) (Specific lat...

Answer Details

To calculate the heat energy required, we need to consider the different stages involved in the process: 1. Heat energy required to melt the ice: This is given by the formula Q = mL, where Q is the heat energy, m is the mass of ice and L is the specific latent heat of fusion of ice. So, Q = 0.1kg x 336,000 J kg^-1 = 33,600 J. 2. Heat energy required to raise the temperature of the melted ice (now water) from 0^oC to 100^oC: This is given by the formula Q = mcΔθ, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and Δθ is the change in temperature. So, Q = 0.1kg x 4200 J kg^-1K^-1 x (100^oC - 0^oC) = 42,000 J. Therefore, the total heat energy required is the sum of the heat energy required for melting the ice and for raising the temperature of the water: 33,600 J + 42,000 J = 75,600 J. Therefore, the answer is 75,600J.