A metal has work function of 4.375 eV Calculate its threshold frequency. (h = 6.6 x 10-34Js; 1eV = 1.6 x 10-19J)
Answer Details
The threshold frequency of a metal is the minimum frequency of light required to eject an electron from its surface.
The formula for calculating the threshold frequency is given by:
Threshold frequency = Work function / Planck's constant
We are given the work function of the metal as 4.375 eV. We need to convert this into joules using the conversion factor 1 eV = 1.6 x 10^-19 J:
Work function = 4.375 x 1.6 x 10^-19 J/eV = 7 x 10^-19 J
We are also given Planck's constant as 6.6 x 10^-34 J s.
Now, substituting the values into the formula, we have:
Threshold frequency = Work function / Planck's constant
Threshold frequency = (7 x 10^-19 J) / (6.6 x 10^-34 J s)
Threshold frequency = 1.06 x 10^15 Hz
Therefore, the threshold frequency of the metal is 1.06 x 10^15 Hz.
Option (ii) is the correct answer.