A car traveling at 30ms\(^{-1}\) overcomes a frictional resistance of 100N while moving. Calculate the power developed by the engine. [1 hp = 0.75 kW]

Assessment: WAEC SSCE - Physics - 2014 (Objective) Subject: Physics

Question 1 Report

A car traveling at 30ms\(^{-1}\) overcomes a frictional resistance of 100N while moving. Calculate the power developed by the engine. [1 hp = 0.75 kW]

Answer Details
Power is the rate at which work is done or the rate at which energy is transferred. In this question, the power developed by the car's engine can be calculated using the formula: Power = force x velocity The force in this case is the frictional resistance, which is 100N, and the velocity is 30ms\(^{-1}\). Therefore, Power = 100N x 30ms\(^{-1}\) = 3000W = 3kW To convert kW to hp, we use the conversion factor 1 hp = 0.75 kW. 3 kW = 3/0.75 hp = 4 hp Therefore, the power developed by the engine is 4 hp, which corresponds to the.

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