The energy stored in a capacitor of capacitance 5μF is 40J. Calculate the voltage applied across its terminals?
Question 1 Report
The energy stored in a capacitor of capacitance 5μF is 40J. Calculate the voltage applied across its terminals?
Answer Details
The energy stored in a capacitor can be expressed as E = 1/2 * C * V^2, where E is the energy stored in the capacitor, C is the capacitance of the capacitor, and V is the voltage applied across its terminals.
From the given information, we have E = 40J and C = 5μF.
Substituting these values into the equation, we get:
40J = 1/2 * 5μF * V^2
Simplifying the equation, we get:
V^2 = (2*40J)/(5μF) = 16,000,000 μV^2
Taking the square root of both sides, we get:
V = 4000μV = 4000V (since 1V = 1,000,000μV)
Therefore, the voltage applied across the terminals of the capacitor is 4000V.
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