A balloon containing 546cm3 of air is heated from 0oC to 10oC. If the pressure is kept constant, what will be its volume at 10oC?
Answer Details
The volume of a gas is directly proportional to its temperature (in Kelvin) at constant pressure, according to Charles's law. This is expressed as V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature, respectively. The temperature must be expressed in Kelvin to avoid negative values, and this is done by adding 273 to the Celsius temperature. Therefore, for this problem, the volume of the balloon at 10°C can be calculated using the following formula:
V1/T1 = V2/T2
V1 = 546 cm^3 (given)
T1 = 0°C + 273 = 273 K
T2 = 10°C + 273 = 283 K (temperature in Kelvin)
Substituting the given values into the formula, we get:
546/273 = V2/283
Solving for V2, we get:
V2 = 546 × 283/273 = 566 cm^3
Therefore, the volume of the balloon at 10°C would be 566 cm^3. Hence, the correct option is (c) 566 cm^3.