Question 1 Report
Calculate the heat energy required to vapourize 50g of water initially at 80oC if the specific heat capacity of water is 4.2Jg-1K (specific latent heat of vapourization of water is 2260Jg-1).
To calculate the heat energy required to vaporize 50g of water initially at 80oC, we need to first calculate the amount of heat energy required to raise the temperature of the water from 80oC to its boiling point, which is 100oC. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we have: Q1 = (50g)(4.2Jg-1K)(100oC - 80oC) = 4200J The amount of heat energy required to vaporize the water at its boiling point can be calculated using the formula Q = mL, where Q is the heat energy, m is the mass, and L is the specific latent heat of vaporization. We have: Q2 = (50g)(2260Jg-1) = 113000J Therefore, the total amount of heat energy required to vaporize 50g of water initially at 80oC is: Qtotal = Q1 + Q2 = 4200J + 113000J = 117200J Thus, the answer is 117200J.