Calculate the heat energy required to vapourize 50g of water initially at 80oC if the specific heat capacity of water is 4.2Jg-1K (specific latent heat of v...

Calculate the heat energy required to vapourize 50g of water initially at 80^oC if the specific heat capacity of water is 4.2Jg^-1K (specific latent heat of vapourization of water is 2260Jg^-1).

Answer Details

To calculate the heat energy required to vaporize 50g of water initially at 80^oC, we need to first calculate the amount of heat energy required to raise the temperature of the water from 80^oC to its boiling point, which is 100^oC. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we have: Q₁ = (50g)(4.2Jg^-1K)(100^oC - 80^oC) = 4200J The amount of heat energy required to vaporize the water at its boiling point can be calculated using the formula Q = mL, where Q is the heat energy, m is the mass, and L is the specific latent heat of vaporization. We have: Q₂ = (50g)(2260Jg^-1) = 113000J Therefore, the total amount of heat energy required to vaporize 50g of water initially at 80^oC is: Q_total = Q₁ + Q₂ = 4200J + 113000J = 117200J Thus, the answer is 117200J.