An engine raises 1000kg of water through a height of 60m in 20s. What is the power of the engine? (Take g = 10ms-2>).

Assessment: WAEC SSCE - Physics - 1989 (Objective) Subject: Physics

Question 1 Report

An engine raises 1000kg of water through a height of 60m in 20s. What is the power of the engine? (Take g = 10ms-2>).
Answer Details
The power of an engine is the rate at which it does work. We can use the formula P = W/t, where P is the power, W is the work done and t is the time taken. In this question, the work done is the product of the force applied and the distance moved in the direction of the force. Since the engine is raising a mass of 1000kg, the force applied is equal to the weight of the water, which is given by F = m*g, where m is the mass and g is the acceleration due to gravity. Thus, F = 1000kg * 10m/s^2 = 10,000N. The distance moved by the water is the height through which it is raised, which is 60m. Therefore, the work done by the engine is given by W = F*d = 10,000N * 60m = 600,000J. Finally, we can substitute these values into the power formula to obtain P = W/t = 600,000J / 20s = 30,000W. Therefore, the power of the engine is 30,000W. Answer: 30,000 W.

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