If a ball released from a height of 20m, How long would it take the ball to reach the ground? (assures g = 10m/s)

The correct answer is "2 seconds". When an object is dropped from a height, it falls under the influence of gravity, which accelerates it downwards. This acceleration due to gravity is denoted by 'g' and has a value of approximately 10 m/s^2 on the surface of the Earth. To determine how long it takes for the ball to reach the ground, we can use the following kinematic equation: d = (1/2) * g * t^2 where 'd' is the distance traveled, 'g' is the acceleration due to gravity, and 't' is the time taken. In this case, the initial height of the ball is 20 m, so we can set 'd' equal to 20 m. We know that 'g' is 10 m/s^2, so we can substitute these values into the equation to get: 20 = (1/2) * 10 * t^2 Simplifying this equation, we get: t^2 = 4 Taking the square root of both sides, we get: t = 2 Therefore, it takes 2 seconds for the ball to reach the ground. So, the correct option is "2 sec".