A body of mass 2kg is released from rest on a plane inclined at an angle of 60° to the horizontal. Calculate the acceleration of the body down the plane.[g ...
Question 1 Report
A body of mass 2kg is released from rest on a plane inclined at an angle of 60° to the horizontal. Calculate the acceleration of the body down the plane.[g = 10ms\(^{-2}\)]
Answer Details
When a body of mass m is released on an inclined plane at an angle θ to the horizontal, the component of its weight acting down the plane is mgsinθ. The force acting parallel to the plane that causes the body to slide down is given by F = mgsinθ. The acceleration of the body down the plane is given by a = F/m = gsinθ.
In this case, m = 2kg and θ = 60°. Therefore, the acceleration of the body down the plane is given by:
a = gsinθ = 10ms\(^{-2}\) x sin(60°) = 8.7ms\(^{-2}\)
Therefore, the correct answer is 8.7ms\(^{-2}\).
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