The current in the primary coil of a transformer is 2.5A. If the coil has 50 turns and the secondary250 turns, calculate the current in the secondary coil. ...

The current in the primary coil of a transformer is 2.5A. If the coil has 50 turns and the secondary250 turns, calculate the current in the secondary coil. Neglect energy losses in the transformer

Answer Details

A transformer is an electrical device that can increase or decrease the voltage of an alternating current. It works on the principle of mutual induction. The current in the primary coil produces a magnetic field that induces a voltage in the secondary coil. According to the law of conservation of energy, the power (P) in the primary coil is equal to the power in the secondary coil. Power is equal to the product of current and voltage (P=IV). Since the transformer is ideal and there are no energy losses, the power in the primary coil is equal to the power in the secondary coil. Therefore, I₁V₁ = I₂V₂ where I₁ and I₂ are the currents in the primary and secondary coils, respectively, and V₁ and V₂ are the voltages in the primary and secondary coils, respectively. We know that the current in the primary coil is 2.5A, the number of turns in the primary coil is 50 and the number of turns in the secondary coil is 250. According to the transformer equation, the voltage in the secondary coil is equal to the voltage in the primary coil multiplied by the ratio of the number of turns in the secondary coil to the number of turns in the primary coil. Therefore, V₂ = V₁ x (N₂/N₁) = V₁ x (250/50) = 5V Now we can calculate the current in the secondary coil using the formula for power: P = IV Since the power in the primary coil is equal to the power in the secondary coil, I₁V₁ = I₂V₂ 2.5A x V₁ = I₂ x 5V I₂ = 2.5A x V₁/5V = 0.5A Therefore, the current in the secondary coil is 0.5A.